Find x 5^{2x-1}-25^{x-1}=2500. If {25^{x 1.25^x+1= 125^-2 find the value of 'x'
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(√5)^x+1=25x
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13. if 52x+1÷25 = 125. find the value of x.[tex]5 {}^{2x + 1} \div 25Squares of 1 Dolomia 29" 1x12Solved -x+25.
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